Java Array Sorting In Ascending Order
Following Java program sort the array in an ascending order without using any pre-define Java class method. We use for loop with conditional statement if-else to sort the array.
Java array soring example
import java.util.Scanner;
public class ArraySorting {
static int n;
public static void input1(int[] b){
Scanner uk=new Scanner(System.in);
System.out.println("Enter " + n + "subject marks");
for(int l=0;l<b.length;l++){
b[l]= uk.nextInt();
}
}
public static void sorting(int[] p){
int i,j;
int temp;
for(i=0;il<n;i++){
for(j=0;j<n-i-1;j++){
if (p[j] > p[j+1]){
temp = p[j];
p[j]=p[j+1];
p[j+1]=temp;
}
}
}
}
public static void display(int[] b){
System.out.println("Sorted Marks:");
for(int l=0;l<b.length;l++){
System.out.println(b[l]);
}
}
public static void main(String[] args) {
Scanner uk=new Scanner(System.in);
System.out.println("Enter the number of element");
n=uk.nextInt();
int x[]=new int[n];
input1(x);
sorting(x);
display(x);
}
}
Output
Enter the number of element 3 Enter 3 subject marks 38 7 120 Sorted Marks: 7 38 120
See Also
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Php is null function
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Exception handling in java
